Thermodynamic
quantities of cell reactions
The
Gibbs free energy change at a given temperature for the overall cell reaction
for an electrochemical cell can be obtained from the reversible e.m.f. (E) of
the cell determined by Poggendorf’s compensation method.
ΔG=
–nF E
where
n is the number of faradays of electricity delivered by the cell. E is positive
by convention and being an intensive quantity, does not depend on how the
stoichiometric equation for the spontaneous overall cell reaction is written.
But ΔG being an extensive quantity does depend on how the overall cell reaction
is written. The same is true about the corresponding enthalpy and the entropy
changes (ΔH and ΔS). These thermodynamic quantities are usually expressed in kJ
mol–1 (ΔS in J K–1 mol–1) when these become intensive quantities.
From
thermo dynamics we have,
Δ
= – [ ∂ΔG/∂T]p
or
ΔS = nF[∂E/∂T]p
since
–ΔG = nF E
The
temperature coefficient of the cell e.m.f., (∂E/∂T)p can be obtained by
determining the e.m.f at various temperatures.
Again
from thermodynamics we have,
ΔG = ΔH – TΔS
Or
–n F E = ΔH – TΔS
or
ΔH = – n F E + TΔS
or ΔH =
– nF E + TnF [ ∂E/∂T]p
Thus
the enthalpy change associated with the overall cell reaction for a reversible cell
can be determined from the reversible e.m.f. (E) and the temperature
coefficient of the reversible e.m.f. of the cell, .The equilibrium constant is
related to standard Gibbs free energy, ΔGO
(or
– n F EO ). Hence we obtain
Since
ΔGO = – RT ln K
Or
– n F EO = – RT ln K
ln K = —[ nF EO/RT]
The
above equation enables one to calculate the equilibrium constant of an overall cell
reaction at a given temperature from the experimentally determined value of the
standard e.m.f. of the cell at the same temperature.
We
have seen earlier that the Weston Cadmium Cell has an e.m.f. (E) of 1.01463 V at
298 K and a temperature coefficient of -5.00 × 10–5 V K–1.
These two data help us to calculate the thermodynamic quantities of the overall
cell reaction.
ΔG
= – n F E
= – 2 × 96500 C mol–1 ×
1.01463 V
= –195824 Jmol-1
ΔS
= nF[ ∂ E/∂T]p
= 2 (96500 C mol–1) × (– 5.00 ×
10–5) V K–1
= – 9.65 Jmol-1
K–1
ΔH
= ΔG + T ΔS
= – 195824 Jmol-1
+
298 K (– 9.65 Jmol-1 K–1)
= -198700 Jmol-1
Electrochemistry II: Voltaic or Galvanic
cells
Suhaschandra Ghosh and Animesh Kumar
Rakshit, 2010, 16
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